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Re: tinkershaw post# 108126

Thursday, 11/04/2010 10:43:26 PM

Thursday, November 04, 2010 10:43:26 PM

Post# of 257253
Tinker: Please see my reply to mcbio in #msg-56321525. You multiply the probabilities that each individual argument fails to get the probability that all of them fail. Then you subtract that from 1.0 to get the probably that at least one argument succeeds, which comes out to 64%. Regards, Dew

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