Anavex Life Sciences Corp (AVXL)

[Doc328]

How can you tell the statistical significance would be p=0.15 when we dont know exact n?

Here's a good link to a T-test calculator. You can also use Excel. If you have SPSS you can do a lot of stats.
Numbers for n at various points were n=170; n=168; n=161 for placebo. I believe these are ITT, mITT and PP(per protocol aka protocol completers) or from safety charts the patients still left after titration. This is so d%^& sloppy to not clearly state n and what it means. This raises sloppy to a new level. Regardless other n is n=338;b=335;n=301 for the A273 cohort of any dose likely ITT, mITT and PP or successfully titrated. There is nothing wrong with using mITT for primary analysis. There is everything wrong with using protocol completers on a slide that says ITT.

For stats, large n gives you better numbers. So I will be generous. and use n=170 for placebo and n=338 for A273, the ITT numbers

Run these numbers in the calculator AS PRESENTED IN THE SLIDE (make sure to use SEM and not SD).
GROUP mean / SEM / n
Placebo 4.11 0.86 170
Anavex 2.26 0.51 338

you get p = 0.0503 so close I don't see where 0.033 came in

If we use the more arithmetically correct numbers then placebo delta baseline to 48 weeks is 4.08 (close to 4.11) and Anavex delta baseline to 48 weeks is 2.74 (not the better 2.26)
GROUP mean / SEM / n
Placebo 4.08 0.86 170
Anavex 2.74 0.51 338

you get p=0.156

They need to quickly tell us what happened and what the real numbers are.

Als, they cannot say they hit the ADCS-ADL primary endpoint with responder analysis and not also report the mean / sem And for good measure, tell us which goup: ITT or PP was used