SPO Networks Inc (SPOI)

[dandy4951]

It's just basic volumetrics but if it's too hard to comprehend then here's a simple example .

Typical A/F ratio in a petrol IC Engine would be about 30:2 (30 parts Air to 2 parts Fuel, in other words a ratio of 15 to 1)

Let's replace some of the air with a little bit of Hydrogen from HLNT's device , let's say just 1 part equivalent volume .

You now have a mixture of 29 parts air , 1 part Hydrogen and 2 parts Fuel. The A/F ratio if considering only Air and Original Fuel alone is now 29 parts to 2 parts or 14.5 to 1 . Wow the A/F ratio is different to what it was without the Hydrogen and I have'nt even touched the ECU or anything like that.

But wait there is more , Hydrogen itself is highly combustible and can be considered to be a "fuel" of its own accord. So we really have a mixture of 29 parts air compare to 3 parts fuel (2 petrol and 1 hydrogen). So based on this the A/F ratio should be expressed to be 29 parts air to 3 parts fuel which equates to 9.66. Again we have'nt changed anything other than introducing some hydrogen into the air /fuel mixture and the ratio is different to what it is without it. How hard can it be to get
that ?