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Re: Chiugray post# 295253

Friday, 07/17/2020 11:43:52 PM

Friday, July 17, 2020 11:43:52 PM

Post# of 700511
P(at least one succeeds) = 1 - P(all fail)

Based on your wildly optimistic assumptions, that would be

1 - (.3 * .3 * .3) = .973 or 97.3%

If you prefer a sports analogy, it's the same math as a 70% free throw shooter with 3 attempts.

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