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Re: zeroedin post# 47402

Thursday, 05/30/2019 2:02:11 AM

Thursday, May 30, 2019 2:02:11 AM

Post# of 56990
Zerodin...your description of a trapped mouse is very good. Same situation for me since 2011. Lately, I am feeling pretty good especially since the arrival of Fluid Dynamics Expert Christopher T. Gallagher (Ph.D.) as a consulting engineer.

Back in February 2014, I had a lengthy fluid dynamics discussion with 'alkalinesolution1' and 'moorea9' about the mechanism by which the AOT increases the volume of crude pushed through a pipe over a given period of time. See Post #6166
It was very interesting to see how everybody had a different understanding of how the AOT works, In the end, we got a response from STWA on the 12th of February 2014.

I received this confirmation directly from Dr. Tao, in an email (compiled by Alkaline).

He said that:
1) the total pressure is the sum of the Delta P (pressure drop) of each section
2) if you reduce the pressure drop in one section, you reduce total pressure as well
3) power is total pressure * flow rate Q
4) so if you reduce pressure drop in one section, you reduce total power
5) however the equation cited is only for laminar flow, and does not apply to a turbulent flow. But the pressure drop question is still the same. There are other equations for determining the situation in turbulent/laminar flow scenarios.

In conclusion, for everyone who has been confused by the science mumbo jumbo: if you put the AOT in the middle of a section of pipeline, you get increased flow. If you put another AOT on, you get more increased flow. If you put AOTs all the way along, you get still more increased flow. One section of treated oil in a pipeline will give you some benefit, and more AOTs will give you more benefit. That is the conclusion of all this.



Then on the 13th of February 2014 STWA submitted a different point of view (Post #6212). Remember back then STWA board was more navy seal and bankers.

To be fair to your friend, this comment:
"Look at the equation: V = velocity in pipe = Q (flow rate through pipe) / A (pipe cross section area)
In a closed system (pipeline) the A is constant and the Q on entry is equal to the Q on exit (conservation of mass), therefore the velocity in the pipe is unchanged."
Is kind of true (actually the equation is Q=VA),



I expect QSEP will have to address fluid dynamic topics such as those discussed on this board back in 2014 with potential customers during the commercialization process. Christopher Gallagher is the right person for the job.
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