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Re: TRCPA post# 2456

Tuesday, 06/08/2004 3:43:10 PM

Tuesday, June 08, 2004 3:43:10 PM

Post# of 53980
TR, the "expected" numbers seem to be as follows:

Prim/Sec Sludge = 4000 lb/hr
De-inking Sludge = 6000 lb/hr
Wood / hog / etc = 8000 lb/hr

These numbers, however, only tell half the story. This is because these numbers are highly dependent on moisture content of the feed material. For example, sludge which is 75% moisture going in, cannot be processed at the same rate as sludge which is 40% moisture. Also, if the desired output moisture content is 25%, then the material can be processed faster then if the desired output moisture content is 10%. I believe that the above numbers assume 50% moisture content going in and about 10-15% coming out. So a better way to look at this is, how much (maximum) water will the KDS be able to remove per hour. This should give a better common denominator.

Using de-inking sludge for example:
INPUT: 50% moisture means that out of 6000 lb/hr, 3000 lb = solid waste and 3000 lb = water.

OUTPUT: 10% moisture remaining means we still have 3000 lb of solid waste plus water which is now 10% of the total output mass (ie. 3000lb solid=90% and X lb water=10%). So we have 333 lb of water left in the product (3333 lb in total)

RESULT: 3000 lb - 333 lb= 2667 lb of water have been removed, or about 89% of the original water in the product. This number should be more consistent (and impressive) and give a better idea of the expected production rates... Or at least so I understand wink

Is that as clear as mud???


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