Solar Wind Energy Tower Inc. (fka SWET)

[dog turd cannon]

800m high and a diameter of ~300m.

That is 56520000 m3 which is 14931050879 gallons in total volume.

Velocity of the air at the orifice let's say is zero.
Velocity of the air at the bottom let's say is 50mph or 22.35 m/s

X = Xo + Vo(t) + 0.5a(t^2).

For simplicity let's say the origin is at the top of the tower and "down" is positive.

So,

X - Xo = 800m = 0.5a(t^2)

V(t) = Vo + at

22.35 = 0 + at

These are simultaneous equations. "a" is the effective acceleration which is gravity minus various things like wind resistance, friction, etc.

Solving for t (time) you get ~ 70 seconds. Which means it takes just over a minute for water at the top that is vapor to sink to the bottom.

Let's figure out the density of the air now. Using 376000 gallons / minute and 70 seconds.

That means there will be ~450000 gallons of water discharged into the cylinder during this time. So that is how much water is in the cylinder at all times with continuous flow.

In order to do anything I need to go back to metric.

450000 gallons of water is 1,703,435 kg. Total volume is 56,520,000 m3 which is a vapor density of ~ 0.03 or 3%.

Using this handy tool

http://hyperphysics.phy-astr.gsu.edu/hbase/kinetic/relhum.html

@ 70 degrees F (the temp at the top) you get a maximum of 18gm/m^3 which is 0.018, 1.8%. So my estimate is two fold high.. but it is just a first order estimate. So, a better flow rate for maximum efficiency is 1.8/3 * 376,000 gallons/minute. The issue is the scale of this tower is hard to really fathom. The amount of water needed to even create a very thin but constantly flowing mist is hard to fathom.