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mas

Re: wbmw post# 48987

Saturday, 09/22/2007 5:09:33 PM

Saturday, September 22, 2007 5:09:33 PM

Post# of 151802
Using a die length of 17.25mm and height of 16.4mm and defect density of 0.57 you get exactly 50 good die out of 205 which is a yield percentage of 24.7%.

Using probability laws this means the yield percentage of one core is 0.705 which gives us the following core yields

Prob(QC) = p^4 = 0.275 or 50 quad-core die
Prob(TC) = 4p^3*(1-p) = 0.413 or 85 tri-core die
Prob(DC) = 6p^2*(1-p)^2 = 0.260 or 53 dual-core die
Prob(SC) = 4p*(1-p)^3 = 0.072 or 15 single-core die
Prob(dud)= (1-p)^4 = 0.008 or 2 no yields

Taking AMD at their word and say DD = 0.49 that gives
60 quads at 29.3% yield and using the above formula that also gives

Prob(QC) = p^4 = 0.293 or 60 quad-core die
Prob(TC) = 4p^3*(1-p) = 0.421 or 86 tri-core die
Prob(DC) = 6p^2*(1-p)^2 = 0.227 or 47 dual-core die
Prob(SC) = 4p*(1-p)^3 = 0.054 or 11 single-core die
Prob(dud)= (1-p)^4 = 0.005 or 1 no yields

Anyway you look at it tri-cores will dominate
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